The correct Answer is:C
To complete the reaction of sodium acetate (CH₃COONa) with sodium hydroxide (NaOH) in the presence of calcium oxide (CaO), we will follow these steps:
1. Identify the Reactants:
The reactants in this reaction are sodium acetate (CH₃COONa) and sodium hydroxide (NaOH), along with calcium oxide (CaO) which acts as a dehydrating agent.
2. Understand the Reaction Type:
This reaction is a decarboxylation reaction, which occurs when a carboxylic acid salt is heated with a strong base and a dehydrating agent. In this case, we are using soda-lime (a mixture of NaOH and CaO).
3. Write the Reaction:
The sodium salt of acetic acid (sodium acetate) reacts with sodium hydroxide and calcium oxide. The decarboxylation process will lead to lớn the formation of methane (CH₄) and sodium carbonate (Na₂CO₃).
The balanced reaction can be written as:
CH3COONa+NaOH+CaO→CH4+Na2CO3
4. Identify the Products:
The products of this reaction are methane (CH₄) and sodium carbonate (Na₂CO₃).
5. Final Equation:
Thus, the complete reaction is:
CH3COONa+NaOH+CaO→CH4+Na2CO3
The reactants in this reaction are sodium acetate (CH₃COONa) and sodium hydroxide (NaOH), along with calcium oxide (CaO) which acts as a dehydrating agent.
This reaction is a decarboxylation reaction, which occurs when a carboxylic acid salt is heated with a strong base and a dehydrating agent. In this case, we are using soda-lime (a mixture of NaOH and CaO).
The sodium salt of acetic acid (sodium acetate) reacts with sodium hydroxide and calcium oxide. The decarboxylation process will lead to lớn the formation of methane (CH₄) and sodium carbonate (Na₂CO₃).
CH3COONa+NaOH+CaO→CH4+Na2CO3
The products of this reaction are methane (CH₄) and sodium carbonate (Na₂CO₃).
Thus, the complete reaction is:
CH3COONa+NaOH+CaO→CH4+Na2CO3